If a 30 ohm resistor in a parallel network carries 2 amperes, the voltage across that resistor is:

If a 30 ohm resistor in a parallel network carries 2 amperes, the voltage across that resistor is:

• A. 15 volts
• B. 30 volts
• C. 60 volts
• D. 90 volts

Answer: (C)

Ohm's law ties current, voltage, and resistance together: V = I × R. In a parallel network, each branch has the same voltage across it, so the voltage across this resistor is determined by its own current and resistance. With a current of 2 A through a 30 Ω resistor, the voltage across it is V = 2 A × 30 Ω = 60 V. So the voltage across that resistor is 60 volts. (For context, the corresponding power would be P = I × V = 2 A × 60 V = 120 W, which also equals I²R = 4 × 30 = 120 W.)

Ohm's law ties current, voltage, and resistance together: V = I × R. In a parallel network, each branch has the same voltage across it, so the voltage across this resistor is determined by its own current and resistance. With a current of 2 A through a 30 Ω resistor, the voltage across it is V = 2 A × 30 Ω = 60 V. So the voltage across that resistor is 60 volts. (For context, the corresponding power would be P = I × V = 2 A × 60 V = 120 W, which also equals I²R = 4 × 30 = 120 W.)